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    On repdigits as product of consecutive Lucas numbers
    (Bulgarian Acad Science, 2018) Irmak, Nurettin; Togbe, Alain
    Let (L-n)(n >= 0 )be the Lucas sequence. D. Marques and A. Togbe [7] showed that if F-n . . . Fn+k-1 is a repdigit with at least two digits, then (k, n) = (1, 10), where (F-n)(>= 0) is the Fibonacci sequence. In this paper, we solve the equation L-n . . . Ln+k-1 = a (10(m) - 1/9) , where 1 <= a <= 9, n, k >= 2 and in are positive integers.